SOLUTION: 1. if a box is to be 2 feet high, and the width is to be three feet less than its length. If it needs to hold a volume of 80 cubic feet, find the length and width of the box.
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-> SOLUTION: 1. if a box is to be 2 feet high, and the width is to be three feet less than its length. If it needs to hold a volume of 80 cubic feet, find the length and width of the box.
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Question 617437: 1. if a box is to be 2 feet high, and the width is to be three feet less than its length. If it needs to hold a volume of 80 cubic feet, find the length and width of the box.
Please help and show me how to solve this! I need an answer ASAP!!
Thanks! Found 2 solutions by MathTherapy, scott8148:Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website! 1. if a box is to be 2 feet high, and the width is to be three feet less than its length. If it needs to hold a volume of 80 cubic feet, find the length and width of the box.
Please help and show me how to solve this! I need an answer ASAP!!
Thanks!
Volume of a rectangular prism (box) = length * width * height
Let length be L
Then width = L - 3
Height = 2
We now have: Volume = length * width * height, OR
80 = L(L - 3)(2)
80 = 2L(L - 3)
------ Factoring out GCF, 2
(L - 8)(L + 5) = 0
L, or length = , or L = - 5 (ignore as measurement CANNOT be negative).
Since length = 8, then width = 8 - 3, or
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