Question 617137: Identify the curve. Find the characteristics listed.
Center, Vertices, Foci.
x^2/64 + y^2/16 = 1
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Identify the curve. Find the characteristics listed.
Center, Vertices, Foci.
x^2/64 + y^2/16 = 1
This is an equation of an ellipse with horizontal major axis.
Its standard form: (x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k)=(x,y) coordinates of center
For given equation:
center: (0,0)
a^2=64
a=√64=8
vertices: (0±a,0)=(0±8,0)=(-8,0) and (8,0)
..
b^2=16
b=√16=4
..
c^2=a^2-b^2=64-16=48
c=√48≈6.93
foci: (0±c,0)=(0±6.93,0)=(-6.93c,0) and (6.93,0)
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