Question 617053: y=3(x+4)^2+1
Vertex, axis of symmetry, x-int, y-int. this graph does not intersect the x=axis
And solve using the quadratic formula
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! y=3(x+4)^2+1
Vertex, axis of symmetry, x-int, y-int.
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This is an equation of a parabola that opens upwards.
Its standard form of equation: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, A=multiplier which affects width or steepness of curve
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For given equation:y=3(x+4)^2+1
Vertex: (-4,1)
axis of symmetry: x=-4
x-int: none (minimum value=1)
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y-int:
set x=0, then solve for y
y=3*4^2+1=49
y-int=49
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