SOLUTION: {{{(3y+1)/2+(y+2)/3=1}}}

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Question 617: %283y%2B1%29%2F2%2B%28y%2B2%29%2F3=1
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
%283y%2B1%29%2F2%2B%28y%2B2%29%2F3=1
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Multiply each term by the LCD = 6
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6%2A%28%283y%2B1%29%2F2%29%2B6%2A%28%28y%2B2%29%2F3%29=6%2A1
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Cancel the denominators into the 6's, and we have:
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3(3y+1) + 2(y+2) = 6
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9y + 3 + 2y + 4 = 6
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11y + 7 = 6
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11y = -1
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y = -1/11
Edwin J