SOLUTION: Sine(60) = 12/hypotenuse then Hypotenuse=12/Sine(60) x= Please help Thank you soo much

Algebra ->  Angles -> SOLUTION: Sine(60) = 12/hypotenuse then Hypotenuse=12/Sine(60) x= Please help Thank you soo much      Log On


   

Question 616990: Sine(60) = 12/hypotenuse then Hypotenuse=12/Sine(60) x= Please help Thank you soo much
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Sine(60) = 12/hypotenuse
then
Hypotenuse = 12/Sine(60)
------------
Hypot = 12/(sqrt(3)/2) = 24/sqrt(3) = (24*sqrt(3))/3 = 8*sqrt(3)
=======================
Cheers,
Stan H.
=======================