SOLUTION: If logN= logA + 3logB, solve for N in terms of A and B.
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Question 616893
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If logN= logA + 3logB, solve for N in terms of A and B.
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If logN= logA + 3logB, solve for N in terms of A and B.
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logN= logA + 3logB
logN= logA + logB^3
logN= logAB^3
N= AB^3