SOLUTION: The difference of the squares is of two numbers is 80% of the sum of their squares . What will be the the ratio of the larger number to the smaller number ?

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Question 616891: The difference of the squares is of two numbers is 80% of the sum of their squares . What will be the the ratio of the larger number to the smaller number ?
Found 2 solutions by ewatrrr, ankor@dixie-net.com:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

The difference of the squares is of two numbers is 80% of the sum of their squares .

What will be the the ratio of the larger numberx to the smaller numbery  ?

 x%5E2-y%5E2+=+.8%28x%5E2+%2By%5E2%29

     .2x^2 = 1.8y^2

      +x%5E2%2Fy%5E2+=+1.8%2F.2+=+9%2F1

       x/y = 3/1

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The difference of the squares of two numbers is 80% of the sum of their squares.
What will be the the ratio of the larger number to the smaller number ?
:
x^2 - y^2 = .8(x^2 + y^2)
x^2 - y^2 = .8x^2 + .8y^2
x^2 - .8x^2 = .8y^2 + y^2
.2x^2 = 1.8y^2
multiply both sides by 5
x^2 = 9y^2
Find the square root of both sides
x = 3y
Ratio of two numbers: 3:1