SOLUTION: How do I solve this? Thank you!! log[2](2x+15)-log[2](x)=3
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Question 616744
:
How do I solve this? Thank you!!
log[2](2x+15)-log[2](x)=3
Answer by
nerdybill(7384)
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applying "log rules":
log[2](2x+15)-log[2](x)=3
log[2](2x+15)/(x)=3
(2x+15)/(x)= 2^3
(2x+15)/x = 8
2x+15 = 8x
15 = 6x
15/6 = x
5/2 = x