SOLUTION: The cost c(x) in dollars of producing x calculators is given c(x)=16000+120x and the revenue R(x) is R(x)=700x-x^2/50. Find the profit P(x), where P(x)=R(x)-C(x), when 500 calcula
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: The cost c(x) in dollars of producing x calculators is given c(x)=16000+120x and the revenue R(x) is R(x)=700x-x^2/50. Find the profit P(x), where P(x)=R(x)-C(x), when 500 calcula
Log On
Question 61666: The cost c(x) in dollars of producing x calculators is given c(x)=16000+120x and the revenue R(x) is R(x)=700x-x^2/50. Find the profit P(x), where P(x)=R(x)-C(x), when 500 calculators are produced and sold. Answer by 303795(602) (Show Source):
You can put this solution on YOUR website! The cost of producing 500 calculators is given by the cost formula
c(x)=16000+120x Substitute x = 500 into this formula.
Cost = 16000 + 120 * 500
= $76 000
The revenue gained from selling the 500 calculators is given by
R(x)=700x-x^2/50. Substitute x = 500 into this formula.
Revenue = 700*500 - 500^2/50
=$345 000
The profit formula is P(x)=R(x)-C(x)
Profit = $345 000 - $76 000
=$269 000
(Note that if only a few calculators were produced then the cost function would be larger than the revenue function and the profit would be negative. This would mean that a loss had been made.)