Question 616512: in a warehouse the speed of the forklift is 1.2 mins per move, the avaerage distance per move is 235feet/move. in one day the sum of all forklift drivers
(30) travel a sum distance of 700000feet, which is equivalent to 2645 move, and we pay the forklift drivers $18.16/hour. my obective is to find out how many feet per hour do they all travel, and use that infomation to find how much we pay them in one hour per feet. The lower the distance per move the less I should pay, but i am using excel and doing the opposite. Please help
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! in a warehouse the speed of the forklift is 1.2 mins per move, the avaerage distance per move is 235feet/move. in one day the sum of all forklift drivers
(30) travel a sum distance of 700000feet, which is equivalent to 2645 move, and we pay the forklift drivers $18.16/hour. my obective is to find out how many feet per hour do they all travel, and use that infomation to find how much we pay them in one hour per feet. The lower the distance per move the less I should pay, but i am using excel and doing the opposite.
---------------------
700000/2645 = 2979 moves
----
Is one day 24 hours?
----------------
to find how much we pay them in one hour per feet.
You stated you pay them $18.16 per hour.
------------
It's not clear what you're trying to find.
|
|
|
