SOLUTION: In the plane xy-plane, which of the following are point os intersection of the circles whose equations are x^2 + y^2 = 4 and (x - 2)^2 + y^2 = 4? A. (-1, sqrt(3)) , (-1, -sqrt (

Algebra ->  Coordinate-system -> SOLUTION: In the plane xy-plane, which of the following are point os intersection of the circles whose equations are x^2 + y^2 = 4 and (x - 2)^2 + y^2 = 4? A. (-1, sqrt(3)) , (-1, -sqrt (      Log On


   

Question 616450: In the plane xy-plane, which of the following are point os intersection of the circles whose equations are x^2 + y^2 = 4 and (x - 2)^2 + y^2 = 4?
A. (-1, sqrt(3)) , (-1, -sqrt (3))
B. (1, sqrt (3)), (1, -sqrt (3))
C. (1, sqrt (3)), (-1, sqrt(3))
D. (1,1), (-1,1)
E. (1,1), (1, -2)
How is it possible that a circle can be expressed by an equation? I am quite perplexed by this... How do you find the point of intersection?
Thank you so much for any help you can give me?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

points of intersection of the circles: *x%5E2+%2B+y%5E2+=+2%5E2 and %28x+-+2%29%5E2+%2B+y%5E2+=+2%5E2?

Sketching and observing circles intersect at x = 1: x%5E2+%2B+y%5E2+=+2%5E2 and y = sqrt%282%5E2+-+1%5E1%29+= ± +sqrt%283%29 

points of intersection are( 1, ± sqrt%283%29 )