SOLUTION: It would be very appreciated if somebody could solve these for me.. sorry for the bad formatting, I'm not used to typing equations. :P 1. 1/4log(2)16 + 1/2log(2)49 = log(2)x

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: It would be very appreciated if somebody could solve these for me.. sorry for the bad formatting, I'm not used to typing equations. :P 1. 1/4log(2)16 + 1/2log(2)49 = log(2)x       Log On


   

Question 616332: It would be very appreciated if somebody could solve these for me.. sorry for the bad formatting, I'm not used to typing equations. :P
1. 1/4log(2)16 + 1/2log(2)49 = log(2)x
2. 4^(3x) = 10
3. log(3)0.1 + 2log(3)x = log(3)2 + log(3)5


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1. 1/4log(2)16 + 1/2log(2)49 = log(2)x
%281%2F4%29%2Alog%282%2C16%29+%2B+%281%2F2%29%2Alog%282%2C49%29+=+log%282%2Cx%29
log%282%2C2%29+%2B+log%282%2C7%29+=+log%282%2Cx%29
log%282%2C14%29+=+log%282%2Cx%29
x = 14
------------------
2. 4^(3x) = 10
3x*log(4) = log(10) = 1
3x = 1/log(4)
x = 1/(3log(4) = 1/log(64)
x =~ 0.55365
----------------
3. log(3)0.1 + 2log(3)x = log(3)2 + log(3)5
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