SOLUTION: What are the solutions for 2(x-4)^2-8=0

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Question 616237: What are the solutions for 2(x-4)^2-8=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

2%28x-4%29%5E2-8=0 Start with the given equation.


2%28x-4%29%5E2=0%2B8Add 8 to both sides.


2%28x-4%29%5E2=8 Combine like terms.


%28x-4%29%5E2=%288%29%2F%282%29 Divide both sides by 2.


%28x-4%29%5E2=4 Reduce.


x-4=%22%22%2B-sqrt%284%29 Take the square root of both sides.


x-4=sqrt%284%29 or x-4=-sqrt%284%29 Break up the "plus/minus" to form two equations.


x-4=2 or x-4=-2 Take the square root of 4 to get 2.


x=4%2B2 or x=4-2 Add 4 to both sides.


x=6 or x=2 Combine like terms.


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Answer:


So the solutions are x=6 or x=2.