SOLUTION: Graph the system of inequalities.
x+2y is less than or equal to 6
2x+y is less thab or equal to 6
x is greater than or equal to 0
y is greater than or equal to 0
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-> SOLUTION: Graph the system of inequalities.
x+2y is less than or equal to 6
2x+y is less thab or equal to 6
x is greater than or equal to 0
y is greater than or equal to 0
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Question 616217: Graph the system of inequalities.
x+2y is less than or equal to 6
2x+y is less thab or equal to 6
x is greater than or equal to 0
y is greater than or equal to 0 Answer by solver91311(24713) (Show Source):
Replace the inequality sign on each inequality with an equals sign. Graph the boundary line. All of your inequalities are geq or leq so use solid boundary lines. After you have graphed each boundary, select a point that is NOT on the boundary. Substitute the coordinate values of the selected point into the original inequality. If the result is a true statement, shade in the side of the line that contains the selected point. If the result is false, shade in the other side of the line. The solution set of the system is the first quadrant quadrilateral that is defined by the overlap of the four shaded areas.
Hint: If you shade your inequalities in the opposite sense to that given, then you will achieve a much more visually appealing and understandable result of the system solution set being completely unshaded and everything else on the plane having some sort of shading. If you do this be sure you annotate your graph so that anyone reading it knows what you are trying to illustrate.
John
My calculator said it, I believe it, that settles it
