SOLUTION: How do I write the following series in sigma notation form? 5+5+(5/2)+(2/6)+(5/24)+...

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Question 616172: How do I write the following series in sigma notation form?
5+5+(5/2)+(2/6)+(5/24)+...

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
5+5+(5/2)+(2/6)+(5/24)+...
Those denominators are factorials:

4! = 4·3·2·1 = 24
3! = 3·2·1 = 6
2! = 2·1 = 2
1! = 1

also 0! is defined as 1.

Therefore the series:

 5 + 5 + 5%2F2 + 5%2F6 + 5%2F24 + ...

is really

 5%2F1 + 5%2F1 + 5%2F2 + 5%2F6 + 5%2F24 + ...

which is really:

 5%2F0%21 + 5%2F1%21 + 5%2F2%21 + 5%2F3%21 + 5%2F4%21 + ... + 5%2Fn%21 + ...

So, the nth term is  5%2Fn%21, where we start n with 0.

We put a S in front of that with n=0 on the

bottom and infinity on the top, since the ellipsis "..." with
nothing after it indicates that it never ends.  So the sigma notation
is

sum%28%285%2Fn%21%29%2Cn=0%2Cinfinity%29

By the way, you can use other letters for the "index" (or "dummy variable")
besides n.

These answers are just as good:

sum%28%285%2Fk%21%29%2Ck=0%2Cinfinity%29, sum%28%285%2Fi%21%29%2Ci=0%2Cinfinity%29, sum%28%285%2Fj%21%29%2Cj=0%2Cinfinity%29, sum%28%285%2Fm%21%29%2Cm=0%2Cinfinity%29, etc.

You can also start the index (or dummy variable) at 1 by subtracting 1
from the dummy variable after the sigma:

sum%28%285%2Fn%21%29%2Cn=0%2Cinfinity%29 is the same as sum%28%285%2F%28n-1%29%21%29%2Cn=1%2Cinfinity%29

In fact you can add any integer to the start of the dummy variable and subtract
the same integer from the dummy variable after the sigma.  For instance,  

sum%28%285%2Fn%21%29%2Cn=0%2Cinfinity%29 is the same as sum%28%285%2F%28n-7%29%21%29%2Cn=7%2Cinfinity%29
number 


Edwin