SOLUTION: Find the slope of the line perpendicular to the line passing through the poings p(6,-1) abd Q(3,-2) Slope of line PG =_____slope of perpendicular

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Question 61617: Find the slope of the line perpendicular to the line passing through the poings p(6,-1) abd Q(3,-2)
Slope of line PG =_____slope of perpendicular

Found 2 solutions by checkley71, ankor@dixie-net.com:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
SLOPE OF THE LINE THROUGH THESE TWO POINTS IS:
(-2+1)/(3-6)
-1/-3
1/3 IS THE SLOPE OF THIS LINE
THUS THE SLOPE OF A PERPENDICULAR LINE IS THE NEGATIVE RECIPRICAL OF THIS SLOPE THUS:
-3 IS THE SLOPE OF A PERPENDICULAR LINE TO THE LINE WITH A SLOPE OF 1/3

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Find the slope of the line perpendicular to the line passing through the points p(6,-1) abd Q(3,-2)
Slope of line PG =_____slope of perpendicular
:
First find the slope of the line PQ: Use slope formula: m = (y2-y1)/(x2-x1)
PQ points: x1 = 6; y1 = -1; x2 = 3; y2 = -2
:
m1 = %28-2-%28-1%29%29%2F%283-6%29 = %28-2%2B1%29%2F-3 = %28-1%29%2F%28-3%29 = +1/3 is the slope of line PQ
:
Call the slope of line perpendicular to PQ, m2:
:
Perpendicular line slopes relationship: m1*m2 = -1
:
(1/3)*m2 = -1
:
m2 = -1/(1/3)
m2 = -1*(3/1)
m2 = -3 is the slope of the perpendicular line
:
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