SOLUTION: Can I please receive assistance with these. Identify the center, vertices, and co vertices (x+4)^2/4 + (y-1)^2/1 =1 25x^2 + y^2 +400x +4y +1579= 0 (x-3)/49 + (y+3)/81 = 1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Can I please receive assistance with these. Identify the center, vertices, and co vertices (x+4)^2/4 + (y-1)^2/1 =1 25x^2 + y^2 +400x +4y +1579= 0 (x-3)/49 + (y+3)/81 = 1      Log On


   

Question 616126: Can I please receive assistance with these.
Identify the center, vertices, and co vertices (x+4)^2/4 + (y-1)^2/1 =1
25x^2 + y^2 +400x +4y +1579= 0
(x-3)/49 + (y+3)/81 = 1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

Note:

Standard Form of an Equation of an Ellipse is %28x-h%29%5E2%2Fa%5E2+%2B+%28y-k%29%5E2%2Fb%5E2+=+1+

where Pt(h,k) is the center and a and b  are the respective vertices distances from center.

Identify the center, vertices, and co vertices 

%28x%2B4%29%5E2%2F4+%2B+%28y-1%29%5E2%2F1+=1 is  %28x%2B4%29%5E2%2F2%5E2+%2B+%28y-1%29%5E2%2F1%5E2+=1  ||C(-4,1), V(-2,1) and V(-6,1) Co vertices (-4,2) and (-4,0)

25x%5E2+%2B+y%5E2+%2B400x+%2B4y+%2B1579=+0 is %28x%2B8%29%5E2%2F1%5E2+%2B+%28y%2B2%29%5E2%2F5%5E2+=+1 ||C(-8,-2), V(-8,3) and V(-8,-7) Co vertices (-3,-2) and (-5,-2)

%28x-3%29%5E2%2F49+%2B+%28y%2B3%29%5E2%2F81+=+1 is %28x-3%29%5E2%2F7%5E2+%2B+%28y%2B3%29%5E2%2F9%5E2+=+1 ||C(3,-3), V(3,6) and V(3,-12) Co vertices (10,-3) and (-4,-3)