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Question 615999: Help?!
I was searching throughout the internet for a video with a detailed explanation of Algebra Conics, but no luck D:
Can anyone please help me with these problems?
It's practice for my final, and I'm just panicking!!
Write the equation in standard form, find the center and radius. ((a CIRCLE))
1)x^2+y^2+4x-6y-3=0
&How would you write an equation in standard form if only given...
2) center at (-3,4) passes through the origin
ANY HELP IS SINCERELY AND GRATEFULLY APPRECIATED!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write the equation in standard form, find the center and radius. ((a CIRCLE))
1)x^2+y^2+4x-6y-3=0
Complete the square on the x and on the y terms.
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x^2+4x+? + y^2-6y+? = 3 + ? + ?
x^2 + 4x + 4 + y^2 -6y + 9 = 3+4+9
(x+2)^2 + (y-3)^2 = 16
Center: (-2,3)
Radius = 4
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How would you write an equation in standard form if only given...
2) center at (-3,4) passes through the origin.
Distance from (0,0) to (-3,4) is the radius.
r = sqrt(3^2+4^2) = sqrt(25) = 5
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Equation:
(x+3)^2 + (y-4)^2 = 25
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Cheers,
Stan H.
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