SOLUTION: factor....... 3A(squared)-22a+7 next problem... simplify 4m+20 over 4m(squared) - 100

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Question 615919: factor.......
3A(squared)-22a+7
next problem...
simplify
4m+20 over 4m(squared) - 100

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you started



Looking at the expression 3a%5E2-22a%2B7, we can see that the first coefficient is 3, the second coefficient is -22, and the last term is 7.


Now multiply the first coefficient 3 by the last term 7 to get %283%29%287%29=21.


Now the question is: what two whole numbers multiply to 21 (the previous product) and add to the second coefficient -22?


To find these two numbers, we need to list all of the factors of 21 (the previous product).


Factors of 21:
1,3,7,21
-1,-3,-7,-21


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 21.
1*21 = 21
3*7 = 21
(-1)*(-21) = 21
(-3)*(-7) = 21

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -22:


First NumberSecond NumberSum
1211+21=22
373+7=10
-1-21-1+(-21)=-22
-3-7-3+(-7)=-10



From the table, we can see that the two numbers -1 and -21 add to -22 (the middle coefficient).


So the two numbers -1 and -21 both multiply to 21 and add to -22


Now replace the middle term -22a with -a-21a. Remember, -1 and -21 add to -22. So this shows us that -a-21a=-22a.


3a%5E2%2Bhighlight%28-a-21a%29%2B7 Replace the second term -22a with -a-21a.


%283a%5E2-a%29%2B%28-21a%2B7%29 Group the terms into two pairs.


a%283a-1%29%2B%28-21a%2B7%29 Factor out the GCF a from the first group.


a%283a-1%29-7%283a-1%29 Factor out 7 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28a-7%29%283a-1%29 Combine like terms. Or factor out the common term 3a-1


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Answer:


So 3a%5E2-22a%2B7 factors to %28a-7%29%283a-1%29.


In other words, 3a%5E2-22a%2B7=%28a-7%29%283a-1%29.


Note: you can check the answer by expanding %28a-7%29%283a-1%29 to get 3a%5E2-22a%2B7 or by graphing the original expression and the answer (the two graphs should be identical).