You can put this solution on YOUR website! 3^(n-2) = 27
take log of both sides of the equation to get:
log(3^(n-2) = log(27)
since log(a^b) = b*log(a), your equation becomes:
(n-2)*log(3) = log(27)
divide both sides of this equation by log(3) to get:
n-2 = log(27)/log(3)
add 2 to both sides of this equation to get:
n = log(27)/log(3) + 2
use the LOG function of your calculator to solve for n to get:
n = 5
replace n with 5 in your original equation to get:
3^(5-2) = 27 which results in:
3^3 = 27 which results in:
27 = 27
original equationis true when you replace n with 5 so the value of n = 5 is good.
