Question 615761: Find all the solution of the equation in the interval (0,2pi)
sec^2x-1=0
&
sinx-2=cosx-2
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find all the solution of the equation in the interval (0,2pi)
sec^2x-1=0
tan^2x=1
tan x=±√1=±1
x=π/4, 3π/4, 5π/4, and 7π/4
..
sinx-2=cosx-2
sinx=cosx
sinx/cosx=1
tanx=1
x=π/4 and 5π/4 in quadrants I and III where tan>0
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