SOLUTION: I know when dividing fractions the second set you flip and then it becomes multiplication. But what if you have three sets?? 8/21 / (-4/7) / 4/3

Algebra ->  Exponents -> SOLUTION: I know when dividing fractions the second set you flip and then it becomes multiplication. But what if you have three sets?? 8/21 / (-4/7) / 4/3      Log On


   



Question 61576: I know when dividing fractions the second set you flip and then it becomes multiplication. But what if you have three sets??
8/21 / (-4/7) / 4/3

Found 2 solutions by stanbon, joyofmath:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
8/21 / (-4/7) / (4/3)
Start "flipping" on the right side
and keep flipping.)
=(8/21)/(-4/7)*(3/4)
Simplify:
=(8/21)/(-3/7)
Flip again:
=(8/21)*(-7/3)
Simplify:
=(8/3)*(-1/3)
= -8/9
Cheers,
stan H.

Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!
I know when dividing fractions the second set you flip and then it becomes multiplication. But what if you have three sets??
8/21 / (-4/7) / 4/3
It all depends on how you group the fractions.
Let's look at a simple example: 40/2/5
If you do 40/2 first and then divide by 5 you get 20/5 = 4.
If you do 2/5 first then divide that into 40 you get 40%2F%282%2F5%29+=+40%2A%285%2F2%29+=+100.
In general, if you have %28a%2Fb%29%2Fc then multiply numerator (a/b) and denominator (c) by 1/c to get %281%2Fc%29%28a%2Fb%29+=+a%2F%28bc%29.
If you have a%2F%28b%2Fc%29 then multiply numerator (a) and denominator (b/c) by c/b to get a%28c%2Fb%29+=+ac%2Fb.
So, see if you can now do the problem. Let me know if you can't.