Question 61532: write down the gradient of:
the line parallel to the line with the equation y=3x-2
the line perpendicular to the line with equation y=3x-2
If P is point (-1,3) and Q is the point (-3,7) find the equation of the line that passes through P and Q.
The points A and B have co-ordinates (a,a^2) and (2b,4b^2) respectively. determine the gradient of line AB in its simplest form.
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! Parallel lines have the same slope.
Line # 1: y=3x-2, m = 3
Line #2: In this case it would be any line with a slope of m = 3
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Perpendicular lines have slopes that are negative reciprocals of each other.
Line #1: y=3x-2 , m = 3
Line +#2: y=(-1/3)x-2, m=(-1/3)
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If P is point (-1,3) and Q is the point (-3,7) find the equation of the line that passes through P and Q.
Use the formula for a slope:
m=(7-3)/-3-(-1)=4/-2=-2
y=mx+b [use the slope-intercept form to solve]
7=(-2)(-3)+b [plug-in the values and solve for b]
7=6+b
7-6=b
1=b [plug-in the y-intercept and the slope to get the equation of the line]
y=-2x+1
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The points A and B have co-ordinates (a,a^2) and (2b,4b^2) respectively. determine the gradient of line AB in its simplest form.
Use the slope form to solve:
m=(4b^2-a^2)/(2b-a)[factor]
m=(2b-a)(2b+2)/2b-a [cancel out]
m=2b+2
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