SOLUTION: A lab technician has one solution that is 80 percent chlorinated, and another that is 40 percent chlorinated. How much of each solution is needed to make a 100 Liter solution that

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Question 615265: A lab technician has one solution that is 80 percent chlorinated, and another that is 40 percent chlorinated. How much of each solution is needed to make a 100 Liter solution that is 50 percent chlorinated?
Found 2 solutions by Alan3354, scott8148:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A lab technician has one solution that is 80 percent chlorinated, and another that is 40 percent chlorinated. How much of each solution is needed to make a 100 Liter solution that is 50 percent chlorinated?
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Do it like this one:
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if a 14% acid solution is mixed with a 19% acid solution to produce 45 gallons of a 15% acid solution how much (in gallons) of each solution should be used?
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f = 14%
n = 19%
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f + n = 45 (total gallons)
14f + 19n = 15*45 (total acid)
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n = 45 - f
Sub for n
14f + 19*(45-f) = 675
14f + 855 - 19f = 675
-5f = -180
f = 36 gallons of 14%
n = 9 gallons of 19%

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(80%)(x) + (40%)(100 - x) = (50%)(100)