SOLUTION: The highest number in a set of consecutive even integers is 40. If the average of all integers in this set is negative, what is the minimum number of integers in this set?

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Question 615246: The highest number in a set of consecutive even integers is 40. If the average of all integers in this set is negative, what is the minimum number of integers in this set?
Answer by richard1234(7193) About Me  (Show Source):
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The average of the integers {-40, -38, ..., 40} is zero. Therefore the average of {-42, -40, -38, ..., 40} will be less than zero. There are 42 integers in that set.