SOLUTION: A swimming pool that is 8m wide by 10m long is surrounded by a sidewalk of uniform width. The area of the sidewalk is 72m^2 by itself. Find the width of the sidewalk and the outer

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Question 615076: A swimming pool that is 8m wide by 10m long is surrounded by a sidewalk of uniform width. The area of the sidewalk is 72m^2 by itself. Find the width of the sidewalk and the outer dimensions of th sidewalk to the nearest hundredth of a meter
Found 2 solutions by scott8148, josmiceli:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(8 + 2w)(10 + 2w) = (8 * 10) + 72 ___ (4 + w)(5 + w) = 76

w^2 + 9w - 56 = 0

use quadratic formula to find w

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the swimming pool is +8%2A10+=+80+ m2
The area of the walkway is +72+ m2
The total area is +80+%2B+72+=+152+ m2
Let the width of the sidewalk = +x+
The combined width is +8+%2B+2x+ m
The combined length is +10+%2B+2x+ m
Now I can say
+%28+8+%2B+2x+%29%2A%28+10+%2B+2x+%29+=+152+
+4%2A%28+4+%2B+x+%29%2A%28+5+%2B+x+%29+=+152+
+20+%2B+5x+%2B+4x+%2B+x%5E2+=+38+
+x%5E2+%2B+9x+-+18+=+0+
Use quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29+%2F+%282%2Aa%29+
+a+=+1+
+b+=+9+
+c+=+-18+
+x+=+%28-9+%2B-+sqrt%28+9%5E2+-+4%2A1%2A%28-18%29+%29%29+%2F+%282%2A1%29+
+x+=+%28-9+%2B-+sqrt%28+81+%2B+72+%29%29+%2F+2+
+x+=+%28-9+%2B-+sqrt%28+153+%29%29+%2F+2+
+x+=+%28-9+%2B+12.37%29+%2F+2+ ( can't use the negative square root )
+x+=++3.37%2F2+
+x+=+1.69+
and
+2x+%2B+8+=+3.38+%2B+8+
+2x+%2B+8+=+11.38+
and
+2x+%2B+10+=+3.38+%2B+10+
+2x+%2B+10+=+13.38+
The width of the walkway is 1.69 m
The dimensions are 11.38 x 13.38 m2
check:
+11.38%2A13.38+=+152.26+
+152.26+-+72+=+80.26+
This looks close enough