SOLUTION: How do I find f(0), f(3) and f(-5) for the following functions: a) f(x) = 7 – 2x b) f(x) = x2 + x I first substituted each number for x in quest

Algebra ->  Functions -> SOLUTION: How do I find f(0), f(3) and f(-5) for the following functions: a) f(x) = 7 – 2x b) f(x) = x2 + x I first substituted each number for x in quest      Log On


   



Question 61502: How do I find f(0), f(3) and f(-5) for the following functions:
a) f(x) = 7 – 2x

b) f(x) = x2 + x
I first substituted each number for x in question a I got :
when x is 0, y = 3.5
when x is 3, y = 2
when x is 5, y = 1
Question b was more hard for me but i stuck it through and these are my answers:
when x is 0, y = 0
when x is 3, y = 1.307
when x is 5, y = 1.781
I am NOT sure of these answers...Please help!!

Answer by kapilsinghi(68) About Me  (Show Source):
You can put this solution on YOUR website!
a)
if x = 0 then f(0) = 7 - 2*0 => y = 7
if x = 1 then f(1) = 7 - 2*1 => y = 4
if x = 2 then f(2) = 7 - 2*2 => y = 3
if x = 3 then f(2) = 7 - 2*3 => y = 1
if x = 5 then f(2) = 7 - 2*5 => y = -3
if x = -1 then f(-1) = 7 - 2*(-1) => y = 7+2 = 9
b) f(x) = x2 + x
if x = 0 then f(0) = 0^2 + 0 => y = 0
if x = 3 then f(3) = 3^2 + 3 => y = 9 + 3 = 12
if x = 5 then f(5) = 5^2 + 5 => y = 25 + 5 = 30

regards
kapil
kapilsinghi123@gmail.com