SOLUTION: the sum of the squares od 3 consecutive postive numbers is 365 find the smallest of the 3

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Question 614989: the sum of the squares od 3 consecutive postive numbers is 365 find the smallest of the 3
Answer by Alan3354(69443) About Me  (Show Source):
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the sum of the squares od 3 consecutive postive numbers is 365 find the smallest of the 3
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365/3 =~ 121
sqrt(121) = 11, the middle number