SOLUTION: 7 percent of tools manufactured by a factory are defective. What is the probability that in a shipment of 625 such tools (a) 8 percent or more, and (b) 7 percent or less will be d

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Question 614918: 7 percent of tools manufactured by a factory are defective. What is the probability that in a shipment of 625 such tools (a) 8 percent or more, and (b) 7 percent or less will be defective?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
7 percent of tools manufactured by a factory are defective. What is the probability that in a shipment of 625 such tools
(a) 8 percent or more are defective?
p = 0.07
std = sqrt[0.07*0.93/625] = 0.0030
z(0.08) = (0.08-0.07)/0.0030 = 3.333..
P(p >= 0.08) = P(z >= 3.33) = normalcdf(3.33,100) = 0.0004291
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(b) 7 percent or less will be defective?
z(0.07) = 0
P(p<= 0.07) = P(z<= 0) = 0.5000
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Cheers,
Stan H.