SOLUTION: A set of data is normally distributed with a mean of 500 and standard deviation of 100. � What would be the standard score for a score of 433? � What percentage

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Question 614879: A set of data is normally distributed with a mean of 500 and standard deviation of 100.
� What would be the standard score for a score of 433?
� What percentage of scores is between 500 and 433?
� What would be the percentile rank for a score of 433?

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
A set of data is normally distributed with a mean of 500 and standard deviation of 100.
� What would be the standard score for a score of 433?
z(433) = (433-500)/100 = -67/100 = -0.67
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� What percentage of scores is between 500 and 433?
z(500) = 0
P(433 < x < 500) = P(-0.67< z <0) = normalcdf(-0.67,0) = 0.2486
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� What would be the percentile rank for a score of 433?
Ans: 0.5000-0.2486 = 0.2514
So Percentile for 433 is 25%ile
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Cheers,
Stan H.