SOLUTION: three men do a piece of work,the first does 7/15,the second does 5/6 of the remainder while the third does the rest. If the rest done by the third person equals 24units,find whole

Algebra ->  Sequences-and-series -> SOLUTION: three men do a piece of work,the first does 7/15,the second does 5/6 of the remainder while the third does the rest. If the rest done by the third person equals 24units,find whole       Log On


   

Question 614773: three men do a piece of work,the first does 7/15,the second does 5/6 of the remainder while the third does the rest. If the rest done by the third person equals 24units,find whole piece of work
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
7/15 by the first
1-7/15=8/15
5/6*8/15=4/9 by the second
=
1/6*8/15 by the third

(1/6*8/15)*x=24
1/3*4/15*x=24
x=270