SOLUTION: Find the vertex of the parabola whose equation in standard form is y = x2 + 8x - 1 (-8, -17) (-8, -1) (-4, -1) (-4, -17) (4, -17)

Algebra ->  Rational-functions -> SOLUTION: Find the vertex of the parabola whose equation in standard form is y = x2 + 8x - 1 (-8, -17) (-8, -1) (-4, -1) (-4, -17) (4, -17)       Log On


   

Question 61471: Find the vertex of the parabola whose equation in standard form is y = x2 + 8x - 1
(-8, -17)
(-8, -1)
(-4, -1)
(-4, -17)
(4, -17)

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertex of the parabola whose equation in standard form is
y = x2 + 8x - 1
= [X^2+2(X)(4)+4^2]-4^2-1
=(X+4)^2-17
SO ITS VERTEX IS AT X=-4...AND Y=-17


(-8, -17)
(-8, -1)
(-4, -1)
(-4, -17)
(4, -17)