Question 614630: Casey leaves home at 10 a.m and drives at an average speed drives at an average speed of 25 mph. Marshall leaves the same house 15 minutes later, and drives the same route, but twice as fast as Casey. At what time will Marshall pass Casey, and how far from home will they be when he does?
I tried this equation for the first question, but I got a negative number.
25t = 50(t+1/4)
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Casey leaves home at 10 a.m and drives at an average speed drives at an average speed of 25 mph.
Marshall leaves the same house 15 minutes later, and drives the same route, but twice as fast as Casey.
At what time will Marshall pass Casey, and how far from home will they be when he does?
:
M's travel time is 1/4 LESS than C's therefore it should be
25t = 50(t-.25)
Remember, once you get the time, you can find the distance, using either trip, they should be the same.
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