SOLUTION: SOLVING SYSTEMS by SUBSTITUTION Solve each system by substitution. check your answer. 2x+3y=0 x+2y=-1

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Question 614613: SOLVING SYSTEMS by SUBSTITUTION
Solve each system by substitution. check your answer.
2x+3y=0
x+2y=-1
Found 2 solutions by asuar010, MathTherapy:
Answer by asuar010(338) About Me  (Show Source):
You can put this solution on YOUR website!
we solve for x and we get x=1-2y and substitute and we get
2%281-2y%29%2B3y=0 then 2-4y%2B3y=0 the 2-y=0 so y=2 and then x=1-4=-3

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
SOLVING SYSTEMS by SUBSTITUTION
Solve each system by substitution. check your answer.
2x+3y=0
x+2y=-1

2x + 3y = 0 ------ eq (i)
x + 2y = - 1 ------ x = - 1 - 2y
2(- 1 - 2y) + 3y = 0 ------ Substituting - 1 - 2y for x in eq (i)
- 2 - 4y + 3y = 0
- y = 2

y = 2%2F-1, or - 2

2x + 3(- 2) = 0 ------ Substituting - 2 for y in eq (i)

2x - 6 = 0

2x = 6

x = 6%2F2, or 3

Solution set: (highlight_green%283%29,highlight_green%28-+2%29)

I'll leave the check up to you!!!

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