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Question 614450: Hi! I'm stuck on a hyperbola question on my homework, could you please help me find the center? 9y^2-16x^2-36y-108=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! find the center?
9y^2-16x^2-36y-108=0
complete the square
9(y^2-4y+4)-16x^2=108+36
9(y-2)^2-16x^2=144
(y-2)^2/16-x^2/9=1
This is an equation of a hyperbola with vertical transverse axis.
Its standard form:(y-k)^2/a^2-(x-h)^2/b^2, (h,k)=(x,y) coordinates of center.
For given equation:(y-2)^2/16-x^2/9=1
center: (0,2)
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