SOLUTION: Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pi

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pi      Log On


   

Question 614366: Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pipe 3 alone require to fill the tank?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Pipe 1 can fill a tank in 4 hours. pipes 1 and 2 together can fill it in 3 hours. pipes 2 and 3 can fill it in 4 hours . How much time would pipe 2 alone and how much time would pipe 3 alone require to fill the
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let x=hrs pipe 2 can do the job alone
1/x=its work rate
let y=hrs pipe 3 can do the job alone
1/y=its work rate
1/4=work rate of pipe 1
sum of individual work rates=work rate when working together
..
1/4+1/x=1/3
1/y+1/x=1/4
subtract
1/4-1/y=1/3-1/4
-1/y=1/3-1/4-1/4=4/12-6/12=-2/12=-1/6
y=6
1/x=1/3-1/4=4/12-3/12=1/12
x=12
ans:
hrs pipe 2 can do the job alone=12
hrs pipe 3 can do the job alone=6