SOLUTION: How do I solve: 7/(2-x) = (10-4x)/(x^2 + 3x - 10)

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Question 614341: How do I solve:
7/(2-x) = (10-4x)/(x^2 + 3x - 10)
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
7/(2-x) = (10-4x)/(x^2 + 3x - 10)
7(x^2+3x-10)=(10-4x)(2-x)
7x^2+21x-70=4x^2-18x+20
3x^2+39x-90=0
x^2+13x-30=0
(x-2)(x+15)=0
x=-15 The only answer.
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Ed