SOLUTION: Solve. sq.root(x^2 - 9) = 4

Algebra ->  Radicals -> SOLUTION: Solve. sq.root(x^2 - 9) = 4      Log On


   



Question 614338: Solve.
sq.root(x^2 - 9) = 4

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Given to solve:
.
sqrt%28x%5E2+-+9%29+=4
.
Square both sides to get:
.
x%5E2+-+9+=+16
.
add 9 to both sides to get rid of the -9 on the left side:
.
x%5E2+=+25
.
Take the square root of both sides to get the two answers:
.
x+=+5 and x+=+-5
.
You can check these two answers by returning to the original equation of:
.
sqrt%28x%5E2+-+9%29+=4
.
and first substituting +5 for x to get:
.
sqrt%285%5E2+-+9%29+=+4
.
Square the 5 and this equation becomes:
.
+sqrt%2825+-+9%29+=+4
.
Do the subtraction on the left side to get:
.
sqrt%2816%29+=+4
.
4 is the square root of 16, so this equation reduces to:
.
4+=+4
.
And since this is true, we know that if x = +5, the equation works and therefore +5 is a solution.
.
Next, return to the original equation of:
.
sqrt%28x%5E2+-+9%29+=4
.
and this time substitute -5 for x to get:
.
sqrt%28%28-5%29%5E2+-+9%29+=+4
.
Square the -5 to again get +25 and this equation becomes:
.
+sqrt%2825+-+9%29+=+4
.
Just like last time do the subtraction on the left side to get:
.
sqrt%2816%29+=+4
.
Again, 4 is the square root of 16, so this equation reduces to:
.
4+=+4
.
And since this is true, we know that if x = -5, the equation works and therefore -5 is also a solution.
.
Hope this helps you to understand the problem a little more and you can see how to solve and check a problem such as this one.
.