SOLUTION: Find the solution(s) on the interval 0 &#8804; theta<2(pi) 2sin^2&#1012; + sin&#1012; = 0

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Question 614300: Find the solution(s) on the interval 0 ≤ theta<2(pi)
2sin^2ϴ + sinϴ = 0
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the solution(s) on the interval 0 ≤ theta<2(pi)
2sin^2ϴ + sinϴ = 0
2*2sinxcosx+sinx=0
sinx(4cosx+1)=0
sinx=0
x=0 and π
or
4cosx+1=0
cosx=-1/4
x≈1.823 and 4.965