SOLUTION: if {{{ log( b, x) = 6 }}} and {{{ log( b, y) = 2 }}} then solve {{{ log( b, (x^2)/y) }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: if {{{ log( b, x) = 6 }}} and {{{ log( b, y) = 2 }}} then solve {{{ log( b, (x^2)/y) }}}       Log On


   

Question 614198: if +log%28+b%2C+x%29+=+6+ and +log%28+b%2C+y%29+=+2+ then solve +log%28+b%2C+%28x%5E2%29%2Fy%29+
Found 3 solutions by scott8148, lwsshak3, Alan3354:
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
logb(x^2 / y) = logb(x^2) - logb(y) = 2 logb(x) - logb(y) = (2 * 6) - 2

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
+log%28+b%2C+x%29+=+6+ and +log%28+b%2C+y%29+=+2+ then solve +log%28+b%2C+%28x%5E2%29%2Fy%29+
**
Given:
logb(x)=6
logb(y)=2
solve:
logb(x^2/y)
=2logb(x)-logb(y)
=2*6-2
=10

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if +log%28+b%2C+x%29+=+6+ and +log%28+b%2C+y%29+=+2+ then solve +log%28+b%2C+%28x%5E2%29%2Fy%29+
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+log%28+b%2C+%28x%5E2%29%2Fy%29+
= 2log%28x%29+-+log%28y%29
= 12 - 2
= 10