SOLUTION: How could I possibly solve these? I've heard there is a "long way" and a "short way" v - 6 = 23 2T + 5T - 3 = 11 X + 9 = 21 - 4

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: How could I possibly solve these? I've heard there is a "long way" and a "short way" v - 6 = 23 2T + 5T - 3 = 11 X + 9 = 21 - 4      Log On


   

Question 61410: How could I possibly solve these? I've heard there is a "long way" and a "short way"
v - 6 = 23
2T + 5T - 3 = 11
X + 9 = 21
-
4
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
v - 6 = 23
v-6+6=23+6
v=29
:
Check does the equation = when v=29?
29-6=23
23=23 We're right!!!
:
2T + 5T - 3 = 11
7T-3=11
7T-3+3=11+3
7T=14
7T/7=14/7
T=2
:
Check does the equation = when T=2?
2(2)+5(2)-3=11
4+10-3=11
11=11 We're right again!!!
:
X%2F4%2B9=21
X%2F4%2B9-9=21-9
X%2F4=12
4X%2F4=4%2812%29
X=48
:
Check does the equation = when x=48?
48%2F4%2B9=21
12+9=21
21=21 We're right agian!!!
:
Don't try and do short cuts until you have the basics down, otherwise, when the problems get harder, you won't be able to do them and you'll get behind quickly.
Happy Calculating!!!