SOLUTION: what is the quadratic equation in standard form for the following root? 1,-6

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: what is the quadratic equation in standard form for the following root? 1,-6      Log On


   



Question 613935: what is the quadratic equation in standard form for the following root? 1,-6
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The roots are
+x+=+1+
+x+=+-6+
----------
Now rewrite these as
+x+-+1+=+0+
+x+%2B+6+=+0+
------------
Now express the product:
+%28+x-1+%29%2A%28+x+%2B+6+%29+=+0+
+x%5E2+-x+%2B+6x+-+6++=+0+
+x%5E2+%2B+5x+-+6+=+0+
The function is:
+f%28x%29+=+x%5E2+%2B+5x+-+6+
Here's a plot:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-16%2C+5%2C+x%5E2+%2B+5x+-+6+%29+