SOLUTION: A train leaves at 10 am and is traveling 55 mph due east. Another train leaves 2 hours after the first train traveling 65 mph due east so that they can catch up to the first train.
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: A train leaves at 10 am and is traveling 55 mph due east. Another train leaves 2 hours after the first train traveling 65 mph due east so that they can catch up to the first train.
Log On
Question 613795: A train leaves at 10 am and is traveling 55 mph due east. Another train leaves 2 hours after the first train traveling 65 mph due east so that they can catch up to the first train. How long does it take the second train to catch up to the first train? What time does the second train catch up to the first train? Found 2 solutions by stanbon, lwsshak3:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A train leaves at 10 am and is traveling 55 mph due east. Another train leaves 2 hours after the first train traveling 65 mph due east so that they can catch up to the first train. How long does it take the second train to catch up to the first train? What time does the second train catch up to the first train?
--------------------------
1st east-bound train DATA:
rate = 55 mph ; time = x hrs ; distance = 55x miles
-------------------------------------------
2nd east-bound train DATA:
rate = 65 mph ; time = x-2 hrs ; distance 65(x-2) = 65x-130 miles
-------------------------------------------
Equation:
distance = distance:
55x = 65x-130
10x = 130
x = 13
Catchup time: 11PM
===========================
Cheers,
Stan H.
===========================
You can put this solution on YOUR website! A train leaves at 10 am and is traveling 55 mph due east. Another train leaves 2 hours after the first train traveling 65 mph due east so that they can catch up to the first train. How long does it take the second train to catch up to the first train? What time does the second train catch up to the first train?
**
let x = time second train catches up to first train.
Distance=travel time*speed
Distance first train traveled=55(x+2)
Distance 2nd train traveled=65x
65x=55(x+2)=55x+110
10x=110
x=11
ans:
Time second train catches up to first train=11 hrs
What time second train catches up to first train=9PM