SOLUTION: what is the axis of symmetry, focus, and equation for directrix for the parabola x=1/16 y^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: what is the axis of symmetry, focus, and equation for directrix for the parabola x=1/16 y^2       Log On


   



Question 613699: what is the axis of symmetry, focus, and equation for directrix for the parabola x=1/16 y^2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
x=1/16 y^2 or 16x = y^2 || This is a parabola opening 'right' Axis of symmetry is y = 0
4p = 16, p = 4 , focal pt(4,0) directrix is x = -4,