SOLUTION: a researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 490 college students showed that 33% of them had, or intended to, cheat on examina
Algebra ->
Probability-and-statistics
-> SOLUTION: a researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 490 college students showed that 33% of them had, or intended to, cheat on examina
Log On
Question 613648: a researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 490 college students showed that 33% of them had, or intended to, cheat on examination. Find the margin of error for the 95% confidence interval.
I have: I don't know the mean to complete Answer by ewatrrr(24785) (Show Source):
Hi,
A poll of 490 college students showed that 33% of them had, or intended to, cheat on examination
Find the margin of error for the 95% confidence interval.
ME = 1.96