SOLUTION: correction: 349 teachers and a sample of 110 of them 66 have doctorates. Estimate the number without doctorates.
I have: p=110/349=.32
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-> SOLUTION: correction: 349 teachers and a sample of 110 of them 66 have doctorates. Estimate the number without doctorates.
I have: p=110/349=.32
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Question 613645: correction: 349 teachers and a sample of 110 of them 66 have doctorates. Estimate the number without doctorates.
I have: p=110/349=.32 Answer by ewatrrr(24785) (Show Source):
Hi,
349 teachers and a sample of 110 of them 66 have doctorates
sample of 110 of them 66 have doctorates
66/110 = .60 or 60% having doctorates (40% w/o in the sample)
349(.40) = 139.6 0r ~140 w/o a doctorate of the 349 teachers