SOLUTION: You need a 90% alcohol solution. On hand, you have a 60 mL of a 20% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain t

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: You need a 90% alcohol solution. On hand, you have a 60 mL of a 20% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain t      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 613567: You need a 90% alcohol solution. On hand, you have a 60 mL of a 20% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain the desired solution?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
You need a 90% alcohol solution. On hand, you have a 60 mL of a 20% alcohol mixture. You also have 95% alcohol mixture. How much of the 95% mixture will you need to add to obtain the desired solution?
.
Let x = amount (mL) of 95% mixture added
then
.95x + .20(60) = .90(x+60)
.95x + 12 = .90x+54
.05x + 12 = 54
.05x = 42
x = 840 mL