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Question 613412: how would you write the conic x^2-14x+y^2+4y-11 into standard form?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! how would you write the conic x^2-14x+y^2+4y-11 into standard form?
You should first write the equation =0
x^2-14x+y^2+4y-11=0
Complete the square
(x^2-14x+49)+(y^2+4y+4)-11-49-4=0
(x-7)^2+(y+2)^2-64=0
(x-7)^2+(y+2)^2=64
This is an equation of a circle with center at (7,-2) and radius of 8.
Standard form of equation for a circle:(x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of the center, r=radius
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