SOLUTION: The probabilities that two students will show up for class are .6 and .8. Find the probability that at least one a) show up for class; b) does not show up for class. [Okay, I s

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Question 613373: The probabilities that two students will show up for class are .6 and .8. Find the probability that at least one a) show up for class; b) does not show up for class.
[Okay, I solved a) (.6 + .8 = 1.4) - [(.6)(.8) = .48] = .92. However, I'm not sure how to solve "b." Any direction and explination is greatly appreciated.] Thanking you in advance, Diane
7.5/25
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The probabilities that two students will show up for class are .6 and .8.
Find the probability that at least one
a) show up for class;
P(x>= 1) = 1 - P(x = 0) = 1 - 0.4*0.2 = 1-0.08 = 0.92
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Find the probability that at least one
b) does not show up for class.
= 1 - P(none do not show up) = 1 - P(both show up) =
= 1 - 0.6*0.8 = 1 - 0.48 = 0.52
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Cheers,
Stan H.
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