SOLUTION: 1. 2^(5-3x)=1/16 how you do this and whats the answer 2. log6x+log6(x-3)=2 how you do this and whats the answer 3. 9^2x(27^(3+x))=1/9 how you do this and whats the answer

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 1. 2^(5-3x)=1/16 how you do this and whats the answer 2. log6x+log6(x-3)=2 how you do this and whats the answer 3. 9^2x(27^(3+x))=1/9 how you do this and whats the answer       Log On


   

Question 613345: 1. 2^(5-3x)=1/16 how you do this and whats the answer
2. log6x+log6(x-3)=2 how you do this and whats the answer
3. 9^2x(27^(3+x))=1/9 how you do this and whats the answer



Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

+2%5E%285-3x%29=1%2F16

+2%5E%285-3x%29=2%5E%28-4%29

      5-3x = -4

        9 = 3x

         3 = x

log6x+log6(x-3)=2

log6(x(x-3)) =2

 6^2 = x(x-3) 

  x^2 -3x -36 = 0

  (x-12)(x+3) = 0

    x = 12  Thowing out negative solution for log6(x)